HomeSubnetting Fundamentals Practice Quiz SeriesSubnetting FundamentalsFull nameEmail addressGenderSelectMaleFemaleOtherPrefer not to sayCurrent statusSelectSchool studentCollege studentWorking professionalJob seekerTeacher/TrainerOther I agree that my details and score may be stored for quiz administration.Start QuizQuestion 1 of 25Subnetting FundamentalsMedium1 mark(s)1. You need an ordinary IPv4 subnet for 50 hosts. Which prefix choices provide enough conventional usable addresses?Select all correct answers./24/27/28/25/26Subnetting FundamentalsHard1 mark(s)2. For 10.25.70.200/18, which statements are correct?Select all correct answers.The broadcast address is 10.25.255.255The broadcast address is 10.25.127.255The network address is 10.25.64.0The subnet mask is 255.255.192.0The network address is 10.25.70.0Subnetting FundamentalsMedium1 mark(s)3. Which addresses belong to subnet 192.168.10.128/27?Select all correct answers.192.168.10.159192.168.10.129192.168.10.160192.168.10.150192.168.10.127Subnetting FundamentalsEasy1 mark(s)4. Which statements about CIDR prefix notation are correct?Select all correct answers./8 corresponds to 255.255.255.0/24 means 24 bits identify the network prefix/16 corresponds to 255.255.0.0/24 means 24 host bitsA larger prefix length leaves fewer host bitsSubnetting FundamentalsEasy1 mark(s)5. Which statements about a /26 IPv4 subnet are correct under conventional subnetting?Select all correct answers.It normally provides 62 usable host addressesIt contains 64 total addressesIts mask is 255.255.255.192Its mask is 255.255.255.224It contains 128 total addressesSubnetting FundamentalsMedium1 mark(s)6. A /24 network is divided into /27 subnets. Which statements are correct?Select all correct answers.Only four /27 subnets fit inside the /24Each ordinary /27 conventionally provides 30 usable host addressesEach /27 contains 32 total addressesEach /27 contains 64 total addressesEight /27 subnets fit inside the /24Subnetting FundamentalsMedium1 mark(s)7. You need an ordinary subnet for 12 host interfaces. Which prefixes provide at least 12 conventional usable host addresses?Select all correct answers./29/28/26/27/30Subnetting FundamentalsMedium1 mark(s)8. A /24 network is divided into /26 subnets. Which statements are correct?Select all correct answers.Each /26 contains 32 total addressesFour /26 subnets fit inside the /24Eight /26 subnets fit inside the /24Each /26 contains 64 total addressesEach ordinary /26 conventionally provides 62 usable host addressesSubnetting FundamentalsEasy1 mark(s)9. For the conventional subnet 192.168.10.0/24, which statements are correct?Select all correct answers.192.168.10.255 is normally a usable host addressThere are 254 conventionally usable host addressesThe subnet contains only 128 total addressesThe network address is 192.168.10.0The directed broadcast address is 192.168.10.255Subnetting FundamentalsMedium1 mark(s)10. Which statements correctly explain how to calculate conventional usable hosts in an ordinary IPv4 subnet?Select all correct answers.Determine the number of host bits from 32 minus the prefix lengthCalculate 2 raised to the number of host bits for total addressesThe prefix length has no effect on host capacityFor ordinary subnets, subtract network and broadcast addresses to obtain conventional usable hostsAlways subtract 4 addresses from every subnetSubnetting FundamentalsEasy1 mark(s)11. Which statements about a conventional /29 subnet are correct?Select all correct answers.It contains 8 total addressesIt contains 16 total addressesIt normally provides 6 usable host addressesIts mask is 255.255.255.248Its mask is 255.255.255.240Subnetting FundamentalsMedium1 mark(s)12. For 172.16.5.100/27, which statements are correct?Select all correct answers.The network address is 172.16.5.64The network address is 172.16.5.96The broadcast address is 172.16.5.159The broadcast address is 172.16.5.127The conventional usable range is 172.16.5.97–172.16.5.126Subnetting FundamentalsEasy1 mark(s)13. Which additional subnet mask and CIDR prefix mappings are correct?Select all correct answers.255.255.255.128 — /24255.255.255.240 — /28255.255.255.224 — /27255.255.255.252 — /29255.255.255.248 — /29Subnetting FundamentalsMedium1 mark(s)14. For 192.168.1.130/25, which statements are correct?Select all correct answers.The network address is 192.168.1.0The broadcast address is 192.168.1.127The network address is 192.168.1.128The broadcast address is 192.168.1.255The conventional usable host range is 192.168.1.129–192.168.1.254Subnetting FundamentalsMedium1 mark(s)15. Which methods help reliably solve IPv4 subnetting questions?Select all correct answers.Determine the subnet from the IP address alone while ignoring its prefixAssume all private addresses use a /24 maskConvert the prefix length to the relevant subnet maskLocate the address between the correct subnet boundariesIdentify the block size in the interesting octetSubnetting FundamentalsHard1 mark(s)16. For 172.16.130.10/20, which statements are correct?Select all correct answers.The broadcast address is 172.16.255.255The broadcast address is 172.16.143.255The subnet mask is 255.255.240.0The network address is 172.16.128.0The network address is 172.16.130.0Subnetting FundamentalsEasy1 mark(s)17. Which statements about a /28 subnet are correct under conventional subnetting?Select all correct answers.It normally provides 14 usable host addressesIt leaves 8 host bitsIts mask is 255.255.255.240Its block size is 32 addressesIt contains 16 total addressesSubnetting FundamentalsEasy1 mark(s)18. Which statements about a /27 IPv4 subnet are correct under conventional subnetting?Select all correct answers.It contains 32 total addressesIts mask is 255.255.255.192Its last-octet block size is 32It normally provides 62 usable hostsIt normally provides 30 usable host addressesSubnetting FundamentalsMedium1 mark(s)19. For 10.10.10.14/29, which statements are correct?Select all correct answers.The network address is 10.10.10.14The conventional usable range is 10.10.10.9–10.10.10.14The broadcast address is 10.10.10.16The network address is 10.10.10.8The broadcast address is 10.10.10.15Subnetting FundamentalsMedium1 mark(s)20. For 10.0.0.70/26, which statements are correct?Select all correct answers.The broadcast address is 10.0.0.127The network address is 10.0.0.64The network address is 10.0.0.0The conventional usable host range is 10.0.0.65–10.0.0.126The broadcast address is 10.0.0.255Subnetting FundamentalsMedium1 mark(s)21. For 192.168.100.200/26, which statements are correct?Select all correct answers.The conventional usable range is 192.168.100.193–192.168.100.254The network address is 192.168.100.128The broadcast address is 192.168.100.223The network address is 192.168.100.192The broadcast address is 192.168.100.255Subnetting FundamentalsMedium1 mark(s)22. For the conventional subnet 192.168.20.64/26, which addresses are usable host addresses?Select all correct answers.192.168.20.127192.168.20.65192.168.20.100192.168.20.64192.168.20.126Subnetting FundamentalsMedium1 mark(s)23. For 192.168.50.35/28, which statements are correct?Select all correct answers.The network address is 192.168.50.32The network address is 192.168.50.16The conventional usable range is 192.168.50.33–192.168.50.46The broadcast address is 192.168.50.47The broadcast address is 192.168.50.63Subnetting FundamentalsMedium1 mark(s)24. Which prefix lengths conventionally provide at least 30 usable host addresses per subnet?Select all correct answers./26/24/29/27/28Subnetting FundamentalsEasy1 mark(s)25. Which subnet mask and prefix pairs are equivalent?Select all correct answers.255.255.255.0 — /24255.255.255.224 — /26255.255.0.0 — /24255.255.255.192 — /26255.255.255.128 — /25PreviousNextSubmit Quiz Related Discover more from SanchitGurukul Subscribe to get the latest posts sent to your email. Type your email… Subscribe
