Practice Quiz SeriesSubnetting FundamentalsFull nameEmail addressGenderSelectMaleFemaleOtherPrefer not to sayCurrent statusSelectSchool studentCollege studentWorking professionalJob seekerTeacher/TrainerOther I agree that my details and score may be stored for quiz administration.Start QuizQuestion 1 of 25Subnetting FundamentalsMedium1 mark(s)1. You need an ordinary IPv4 subnet for 50 hosts. Which prefix choices provide enough conventional usable addresses?Select all correct answers./24/28/27/26/25Subnetting FundamentalsEasy1 mark(s)2. Which statements about a /28 subnet are correct under conventional subnetting?Select all correct answers.It normally provides 14 usable host addressesIts block size is 32 addressesIt contains 16 total addressesIts mask is 255.255.255.240It leaves 8 host bitsSubnetting FundamentalsMedium1 mark(s)3. Which prefix lengths conventionally provide at least 30 usable host addresses per subnet?Select all correct answers./29/27/28/24/26Subnetting FundamentalsHard1 mark(s)4. For 172.16.130.10/20, which statements are correct?Select all correct answers.The network address is 172.16.130.0The subnet mask is 255.255.240.0The network address is 172.16.128.0The broadcast address is 172.16.255.255The broadcast address is 172.16.143.255Subnetting FundamentalsMedium1 mark(s)5. For the conventional subnet 192.168.20.64/26, which addresses are usable host addresses?Select all correct answers.192.168.20.64192.168.20.127192.168.20.126192.168.20.65192.168.20.100Subnetting FundamentalsMedium1 mark(s)6. For 10.10.10.14/29, which statements are correct?Select all correct answers.The network address is 10.10.10.14The broadcast address is 10.10.10.15The conventional usable range is 10.10.10.9–10.10.10.14The network address is 10.10.10.8The broadcast address is 10.10.10.16Subnetting FundamentalsMedium1 mark(s)7. A /24 network is divided into /27 subnets. Which statements are correct?Select all correct answers.Each /27 contains 64 total addressesEight /27 subnets fit inside the /24Each ordinary /27 conventionally provides 30 usable host addressesEach /27 contains 32 total addressesOnly four /27 subnets fit inside the /24Subnetting FundamentalsEasy1 mark(s)8. Which additional subnet mask and CIDR prefix mappings are correct?Select all correct answers.255.255.255.248 — /29255.255.255.240 — /28255.255.255.252 — /29255.255.255.128 — /24255.255.255.224 — /27Subnetting FundamentalsEasy1 mark(s)9. Which statements about a conventional /29 subnet are correct?Select all correct answers.It normally provides 6 usable host addressesIts mask is 255.255.255.240It contains 16 total addressesIts mask is 255.255.255.248It contains 8 total addressesSubnetting FundamentalsMedium1 mark(s)10. For 192.168.1.130/25, which statements are correct?Select all correct answers.The conventional usable host range is 192.168.1.129–192.168.1.254The network address is 192.168.1.128The broadcast address is 192.168.1.255The broadcast address is 192.168.1.127The network address is 192.168.1.0Subnetting FundamentalsMedium1 mark(s)11. For 192.168.100.200/26, which statements are correct?Select all correct answers.The network address is 192.168.100.192The broadcast address is 192.168.100.223The conventional usable range is 192.168.100.193–192.168.100.254The network address is 192.168.100.128The broadcast address is 192.168.100.255Subnetting FundamentalsHard1 mark(s)12. For 10.25.70.200/18, which statements are correct?Select all correct answers.The network address is 10.25.64.0The broadcast address is 10.25.255.255The subnet mask is 255.255.192.0The broadcast address is 10.25.127.255The network address is 10.25.70.0Subnetting FundamentalsEasy1 mark(s)13. Which subnet mask and prefix pairs are equivalent?Select all correct answers.255.255.255.224 — /26255.255.255.128 — /25255.255.255.0 — /24255.255.0.0 — /24255.255.255.192 — /26Subnetting FundamentalsMedium1 mark(s)14. You need an ordinary subnet for 12 host interfaces. Which prefixes provide at least 12 conventional usable host addresses?Select all correct answers./28/30/26/27/29Subnetting FundamentalsEasy1 mark(s)15. Which statements about a /27 IPv4 subnet are correct under conventional subnetting?Select all correct answers.Its mask is 255.255.255.192It normally provides 30 usable host addressesIts last-octet block size is 32It contains 32 total addressesIt normally provides 62 usable hostsSubnetting FundamentalsMedium1 mark(s)16. Which methods help reliably solve IPv4 subnetting questions?Select all correct answers.Assume all private addresses use a /24 maskIdentify the block size in the interesting octetConvert the prefix length to the relevant subnet maskDetermine the subnet from the IP address alone while ignoring its prefixLocate the address between the correct subnet boundariesSubnetting FundamentalsMedium1 mark(s)17. Which statements correctly explain how to calculate conventional usable hosts in an ordinary IPv4 subnet?Select all correct answers.For ordinary subnets, subtract network and broadcast addresses to obtain conventional usable hostsCalculate 2 raised to the number of host bits for total addressesAlways subtract 4 addresses from every subnetThe prefix length has no effect on host capacityDetermine the number of host bits from 32 minus the prefix lengthSubnetting FundamentalsEasy1 mark(s)18. Which statements about CIDR prefix notation are correct?Select all correct answers./24 means 24 bits identify the network prefix/16 corresponds to 255.255.0.0A larger prefix length leaves fewer host bits/8 corresponds to 255.255.255.0/24 means 24 host bitsSubnetting FundamentalsEasy1 mark(s)19. For the conventional subnet 192.168.10.0/24, which statements are correct?Select all correct answers.The subnet contains only 128 total addressesThere are 254 conventionally usable host addressesThe directed broadcast address is 192.168.10.255192.168.10.255 is normally a usable host addressThe network address is 192.168.10.0Subnetting FundamentalsMedium1 mark(s)20. A /24 network is divided into /26 subnets. Which statements are correct?Select all correct answers.Each ordinary /26 conventionally provides 62 usable host addressesFour /26 subnets fit inside the /24Each /26 contains 64 total addressesEight /26 subnets fit inside the /24Each /26 contains 32 total addressesSubnetting FundamentalsMedium1 mark(s)21. For 10.0.0.70/26, which statements are correct?Select all correct answers.The conventional usable host range is 10.0.0.65–10.0.0.126The broadcast address is 10.0.0.127The network address is 10.0.0.0The broadcast address is 10.0.0.255The network address is 10.0.0.64Subnetting FundamentalsMedium1 mark(s)22. For 192.168.50.35/28, which statements are correct?Select all correct answers.The broadcast address is 192.168.50.63The network address is 192.168.50.16The network address is 192.168.50.32The broadcast address is 192.168.50.47The conventional usable range is 192.168.50.33–192.168.50.46Subnetting FundamentalsMedium1 mark(s)23. For 172.16.5.100/27, which statements are correct?Select all correct answers.The conventional usable range is 172.16.5.97–172.16.5.126The network address is 172.16.5.96The broadcast address is 172.16.5.159The broadcast address is 172.16.5.127The network address is 172.16.5.64Subnetting FundamentalsEasy1 mark(s)24. Which statements about a /26 IPv4 subnet are correct under conventional subnetting?Select all correct answers.It normally provides 62 usable host addressesIt contains 128 total addressesIts mask is 255.255.255.192Its mask is 255.255.255.224It contains 64 total addressesSubnetting FundamentalsMedium1 mark(s)25. Which addresses belong to subnet 192.168.10.128/27?Select all correct answers.192.168.10.160192.168.10.150192.168.10.159192.168.10.127192.168.10.129PreviousNextSubmit Quiz Related Discover more from SanchitGurukul Subscribe to get the latest posts sent to your email. Type your email… Subscribe Previous article ☟IPv4 Addressing FundamentalsRead the guideNext article ☟Ethernet & MAC AddressingRead the guide
